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16x^2-67x+66=0
a = 16; b = -67; c = +66;
Δ = b2-4ac
Δ = -672-4·16·66
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-67)-\sqrt{265}}{2*16}=\frac{67-\sqrt{265}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-67)+\sqrt{265}}{2*16}=\frac{67+\sqrt{265}}{32} $
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